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Grade: 12th pass
        three distinguishable dices are rolled in how many ways we can get the total 15?
2 years ago

Answers : (1)

Arun
23742 Points
							
Dear Sohan
 
Number of triplets favourable to the event that the sum of the faces of three dice is 15 is (6,6,3),(6,5,4),(6,4,5),(6,3,6),(5,6,4),(5,5,5),(5,4,6),(4,6,5),(4,5,6) and (3,6,6). Hence, the required probability = 10 * 1/216 = 5/108
 
Regards
Arun (askIITians forum expert)
2 years ago
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