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`        Three dice are thrown simultaneously. The probability that 4 has appeared on two dice given that 5 has occurred on one dice is  a.1/6 b.3/91 c.3/216 d.none of these  `
11 months ago

Saurabh Koranglekar
3161 Points
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11 months ago
Muskan soni
13 Points
```							We need to know the favourable cases and the new sample spaceNo. Of pairs has to counted(5,1,1) (5,1,2)............(5,1,6)(5,2,1) (5,2,2)............(5,2,6).............................(5,6,6)6×6=36 cases Now considering series of 1(1,1,1) (1,1,2).............(1,1,5) (1,1,6)                                      (1,2,5)                                      (1,3,5)                                      (1,4,5)(1,5,1)(1,5,2)(1,5,3)(1,5,4)(1,5,5)(1,5,6)                                      (1,6,5)11 pair sets in each series5 such series of (1,2,3,4,6)5 already counted having 36 setsTotal cases =5×11 +36Total cases = 91(new sample space)Favourable cases = (4,4,5)(4,5,4)(5,4,4)Prob = 3/91
```
8 months ago
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• Mind Map
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