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Grade: 12th pass 
        These questions are from permutations combination please solve questions 40,41,42
one year ago

Answers : (1)

Nishant Vora
IIT Patna
askIITians Faculty
2468 Points 
							distance travelled on kth day =k (2^{n+1-k})

Total distance travelled =\sum_{k=1}^{n}k (2^{n+1-k})

\sum_{k=1}^{n}k (2^{n+1}{2^-k})
\sum_{k=1}^{n}k (2^{n+1}){2^{-k}}

(2^{n+1})\sum_{k=1}^{n}k {2^{-k}}
one year ago
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