Dear student
As we know
Total plants in original condition =
= 1*1 + 2*2 + 3*3 + 4*4 +........n²
= 1² + 2² +3² + 4² +......+ n²
= n(n+1)(2n+1)/6
Now
As in a particular row plants has been doubled let assumed row is K th.
Hence..
(1² +2²+3³+4²+....+n²) + k² = 900
n(n+1)(2n+1)/6 + k² = 900
k² = 900 - n(n+1)(2n+1)/6
RHS should be a complete square because row is an integer.
This is satisfied only when n = 13
Now
k² = 900 - 819
k² = 81
k = 9
Hence that particular row is 9th row.
Regards
Arun (askIITians forum expert)