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Grade: 11 

                        
There are n A.M.’s betweeen 3 and 29 such that 6 th mean : (n-1)th mean :: 3:5 then find the valueof n
3 years ago

Answers : (1)

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137 Points 
							The general term[A(r)] = [(n-r+1)a+rb]/n+1 where a is first term and b is last term. Now put first r=6 and then r=n-1 and put in the equation u will get the value of n=12
3 years ago
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