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the w be the cube root of 1 other than 1.the number of orderd pairs (a,b),where a,b belongs to z(set of all integers) such that (aw+b)(aw^2+b)=1 is

the w be the  cube root of 1 other than 1.the number of orderd pairs (a,b),where a,b belongs to z(set of all integers) such that (aw+b)(aw^2+b)=1 is

Grade:12th pass

1 Answers

Aditya Gupta
2081 Points
5 years ago
open the brackets
b^2 – ba+a^2 =1
or (2b-a)^2= 4 – 3a^2
so  4 – 3a^2 greater than equal to zero
so a can only be either – 1, 0, 1
when a=0, b= – 1 or 1
when a=1, b=0 or 1
when a= – 1, b= 0 or – 1
so, the no of orderd pairs (a,b) is 6.

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