The vapour pressure of pure water at 30°C is 31.80 mm of hg. How many grams of urea(molecular mass =60) should be dissolved in 1000 g of water to lower the vapour pressure by 0.25 mm of hg?
Manan patidar , 6 Years ago
Grade 12
1 Answers
Arun
Last Activity: 6 Years ago
As we know
p° - p /p° = W2 M1 /M2 W1
Now put the values
0.25 /31.8 = W2 *18 /(60* 100)
On calculation,
W2 = 2.62 gm
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