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The vapour pressure of pure water at 30°C is 31.80 mm of hg. How many grams of urea(molecular mass =60) should be dissolved in 1000 g of water to lower the vapour pressure by 0.25 mm of hg?

Manan patidar , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

As we know
 
p° - p /p° = W2 M1 /M2 W1
 
Now put the values
 
0.25 /31.8 = W2 *18 /(60* 100)
 
On calculation,
 
W2 = 2.62 gm

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