Dear student,
Please find the solution to your problem.
We know, nCr/nCr-1 = (n – r + 1)/r
Hence, ∑ r. nCr/nCr-1 = ∑ (n – r + 1) [from r = 1 to r = 10]
= ∑ (n + 1) – ∑ r
= 10(n + 1) – 10(10 + 1)/2
= 10n + 10 – 55
= 10n – 45
= 5(2n – 9)
Thanks and regards,
Kushagra