Grade 12th passAlgebrathe value of cos 20+8 sin70*sin 50*sin 10/sin^2(80) is equal to twisha 8 Years agoGrade 12th pass
Arun8 Years agoDear student Sin10sin50sin70 = 2sin10cos10sin50sin70/2cos10 = sin20sin50sin70/2cos10 = 2sin20cos20cos40/4cos10 = 2sin40cos40/8cos10 = sin80/8sin80 = 1/8 cos20 + 8sin10sin50sin70 = cos20 + 1 = 2cos²10 = 2sin²80 (cos20 + 8sin70sin50sin10)/sin²80 = 2. RegardsArun (askIITians forum expert)