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`        The value of 2*1!  +  5*2!  +  10*3!  +17*4!..... till 10 terms is :what i did for this was break it into two parts.. general term : (n^2 +1)n! ∑n^2(n)!  +∑n! i simplified the second term to (n+1)!-1, by the method of shifting the sum and subtracting it from itself (because it is an agp), the value i got for the second part is :  (11)!-1 i cannot figure out how to find the sum of the first part,please help!also please tell me if I was doing the right thing.Thank You.`
one year ago

Heisenberg
12 Points
```							Sorry my bad the sum of the second part is wrong due to a calculation mistake,so now the sum of both the parts are remaining to be found.
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions