Flag Algebra> the value of 2 1/3+lg 2 (121)^1/3 is : 12...
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the value of 21/3+lg2(121)^1/3 is :\t121\t61\t242\tnota

ANANYA VERMA , 8 Years ago
Grade 9
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Write,
 21/3 = >  21/3log2(base 2)  = >   2log2^1/3(base 2)
the expression becomes:
2log2^1/3(base 2) + lg2(121)^1/3
=> 2log2(121)^1/3*(2)^1/3
=> 2log2(121*2)^1/3
=>2log2(242)^1/3
=> (242)^1/3 is the answer.

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