Vikas TU10 Years agoWrite, 21/3 = > 21/3log2(base 2) = > 2log2^1/3(base 2)the expression becomes:2log2^1/3(base 2) + lg2(121)^1/3=> 2log2(121)^1/3*(2)^1/3=> 2log2(121*2)^1/3=>2log2(242)^1/3=> (242)^1/3 is the answer.