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Grade 9Algebra

the value of 21/3+lg2(121)^1/3 is :
  1. 121
  2. 61
  3. 242
  4. nota

Profile image of ANANYA VERMA
10 Years agoGrade 9
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1 Answer

Profile image of Vikas TU
10 Years ago
Write,
 21/3 = >  21/3log2(base 2)  = >   2log2^1/3(base 2)
the expression becomes:
2log2^1/3(base 2) + lg2(121)^1/3
=> 2log2(121)^1/3*(2)^1/3
=> 2log2(121*2)^1/3
=>2log2(242)^1/3
=> (242)^1/3 is the answer.