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The value of ( 1/(1+12+14) ) + ( 2/(1+22+24) ) + ( 3/(1+32+34) ) + .... + ( 99/(1+992+99) ) lies between:A. 0.46 and 0.47 B. 0.47 and 0.48 C. 0.48 and 0.49 D. 0.49 and 0.50

The value of ( 1/(1+12+14) ) + ( 2/(1+22+24) ) + ( 3/(1+32+34) ) + .... + ( 99/(1+992+99) ) lies between:A. 0.46 and 0.47 B. 0.47 and 0.48 C. 0.48 and 0.49 D. 0.49 and 0.50

Grade:10

2 Answers

Akshay
185 Points
6 years ago
there is a mistake in the choices. the sum of the series, will lie between 4.8 and 4.9 and not 0.48 and 0.49.
Also, last term shud be 99/(1+992+994). The sum of the first ten terms is itself comparable to 0.5.You can do the mathematics
Rahul Jiji George
42 Points
6 years ago
i didnt quite understand what you meant ,,,,,,
      can you please,,,,,,,,,,, show it,,,,,,,, step by step

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