The sum of three numbers in H.P. is 24 and the sum of their reciprocals is 1/2.Then the numbers are ?

Hello student,
Please find the answer to your question below
let the 3 numbers are 1/a-d,1/a,1/a+d
as sum of reciprocals is ½
3a=1/2 so a=1/6
and also given their sum is 24
so (6/1-6d)+(6)+(6/1+6d)=24
above eqquation on solving gives d=1/6
so the numbers are (-1/6),(1/6),(+1/6)