Grade 12Algebra
The sum of the values of x satisfying the equation 233x–2 + 211x+2 = 222x+1 + 1 is
The sum of the values of x satisfying the equation 233x–2 + 211x+2 = 222x+1 + 1 is
2 Answers
Vikas TU
Dear student
233x–2 + 211x+2 -222x+1 = 1
Take log on both side
33x-2 + 11x +2 -22x-1 = 0
22x = 1
x = 1/22
Hope this helps
Aditya Gupta
once again, vikas’s answer is the most stupid, childish and wrong answer you can expect. he doesnt even know how to use logarithms.
correct method is as follows:
233x–2 + 211x+2 = 222x+1 + 1
multiply with 2^2 both sides
233x + 211x+4 = 222x+3 + 4
or 233x + 211x*24 = 222x*23 + 4
now, let y= 211x so that y^2= (211x )^2= 211x*2 = 222x and y^3= 2^33x
so we have y^3 + 16y= 8y^2 + 4.
you can easily solve this polynomial eqn and you ll get 3 roots y0, y1 and y2. reject the negtive roots (if any).
the value of x would then be [log2(y)]/11.
kindly approve :)
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