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`        The sum of the values of x satisfying the equation 233x–2 + 211x+2 = 222x+1 + 1 is`
4 months ago

```							Dear student  233x–2 + 211x+2 -222x+1  = 1 Take log on both side 33x-2 + 11x +2 -22x-1 = 0 22x = 1 x = 1/22 Hope this helps
```
4 months ago
```							once again, vikas’s answer is the most stupid, childish and wrong answer you can expect. he doesnt even know how to use logarithms.correct method is as follows:233x–2 + 211x+2 = 222x+1 + 1multiply with 2^2 both sides233x + 211x+4 = 222x+3 + 4or 233x + 211x*24 = 222x*23 + 4now, let y= 211x so that y^2= (211x )^2= 211x*2 = 222x  and y^3= 2^33xso we have y^3 + 16y= 8y^2 + 4.you can easily solve this polynomial eqn and you ll get 3 roots y0, y1 and y2. reject the negtive roots (if any).the value of x would then be [log2(y)]/11.kindly approve :)
```
4 months ago
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