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Grade: 12
        
The sum of the values of x satisfying the equation 233x–2 + 211x+2 = 222x+1 + 1 is
4 months ago

Answers : (2)

Vikas TU
10498 Points
							
Dear student 
 233x–2 + 211x+2 -222x+1  =
Take log on both side 
33x-2 + 11x +2 -22x-1 = 0 
22x = 1 
x = 1/22 
Hope this helps 
 
 
4 months ago
Aditya Gupta
1905 Points
							
once again, vikas’s answer is the most stupid, childish and wrong answer you can expect. he doesnt even know how to use logarithms.
correct method is as follows:
233x–2 + 211x+2 = 222x+1 + 1
multiply with 2^2 both sides
233x + 211x+4 = 222x+3 + 4
or 233x + 211x*24 = 222x*23 + 4
now, let y= 211so that y^2= (211)^2= 211x*2 222x  and y^3= 2^33x
so we have y^3 + 16y= 8y^2 + 4.
you can easily solve this polynomial eqn and you ll get 3 roots y0, y1 and y2. reject the negtive roots (if any).
the value of x would then be [log2(y)]/11.
kindly approve :)
4 months ago
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