Apoorv Tiwari
Last Activity: 5 Years ago
as, (x^2-5x+5)^x^2+4x-60 = 1 = (x^2-5x+5)^0,
=> (x^2+4x-60) = 0
=> x = -10 and 6
and,
(x^2-5x+5) = 0 or -1
now if (x^2-5x+5) = 0
then it wont satisfy original eqn,
if (x^2-5x+5) = 1
x = 4 and 1
if (x^2-5x+5) = -1
x = 2 and 3
now x =3 doesn't satisfy the equation
Hence solutions are -10,6,4,1 and 2
so the sum of solutions = -10+6+4+1+2 = 3
Answer: 3