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The smallest positive integral value of n for which {1 + i sqrt(3)} ^ n/2 is positive is : a)3 b)6 c)12 d)0 Clearly, {1 + i sqrt(3)} ^ n/2 = (-2)^n/2 * (w)^n/2 therefore, if n=6 then it becomes (-2)^3 which would result in a negative number not positive. Please explain how 6 is the answer. I think 12 will be the answer.
Dear student 2^n/2 (– 1)^n/2{ – 1/2 – i sqrt(3)/2} ^ n/2 Now if n = 6 This will results in a positive number
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