Ashwin
Last Activity: 10 Years ago
hi,
Since the sides are in A.P let the sides be x , x + d and x + 2d.
now since smallest side is 10
therefore x = 10
=> sides are 10 , 10 + d and 10 + 2d
we know that sum of any two sides of a triangle is greater than the third side
=> 20 + d > 10 +2d
=> 10 + d > 2d
since we know that the sign of d = + therefore we can subtract d
10 > d
=> d
since the sides are positive integers
therefore ,
d can hold the values 1 , 2 ,3 ….., 9
therefores number of triangles which are possible is 9 .
Regards,
Ashwin