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# The resistance of a bulb filament is 100 ? at a temperature of 100°C. If its temperature coefficient of resistance be 0.005 per °C, its resistance will become 200 ? at a temperature of ?

SHAIK AASIF AHAMED
7 years ago
Hello student,
From the given data when applied to the formula R0=R(1+alpha∆t) we get
200 = 100[1 +(0.005 × ∆t)]
T− 100 = 200
T = 300° C
Thanks and Regards
Shaik Aasif
Ketan Prakash
31 Points
2 years ago
When variation in temperature is more then,
R¹=R(1+alpha Δt) can not be used we have to use   R¹=R e ^(alphaΔt)
Because we can not Neglect any effect on changing hind temperature.
R¹/R= e^(alpha Δt)
ln(R¹/R)=alpha Δt
Hence the correct answer is 240 degree celsius.