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The region of the complex plane for which |z - a|/|z + ~a| = 1 (Re(a) is not equal to 0) is,a)x-axisb)y-axisc)the straight line x=ad)none of theseWhich option is correct?? Please explain.

Meghendra Agrawal , 6 Years ago
Grade
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
If we open this we get
 
|z – a| = |z+a|
 
 
hence z is a locus which is always at same distance from (a , 0) and ( – a, 0).
hence Z will be at perpendicular bisector of both points i.e. Y axis.
 
Hence option B is correct

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