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THe point with position vectors (2,6), (1,2) and (p,10) are collinear if the value of p is ?

sudhanshu , 11 Years ago
Grade 12
anser 1 Answers
Latika Leekha

Last Activity: 10 Years ago

The given points are (2,6), (1,2) and (p,10).
for the points to be collinear, the detreminant should be zero.
Hence, we must have the value of the determinant as zero.
242-685_Capture.PNG
This gives 2(2-10) - 1(6-10) + p (6-2) = 0.
Hence, -16 + 4+ 4p = 0.
This yields 4p = 12.
Hence, p = 3.
Hence, for p = 3, the following points will be collinear.
Thanks & Regards
Latika Leekha
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