the pair of tangent from (2,1) to the circle x^2+y^2=4^2 is\t3x^2+4xy+16x+8y+20=0\t3x^2+4xy+16x-8y+20=0\t3x^2+4xy-16x-8y+20=0\t3x^2-4xy-16x+8y-20=0please give a proper solution

Mrunal Sonawane , 5 Years ago

Grade 12