Algebra> the number of ways in which 6 different b...
1 AnswersLast Activity: 7 Years ago
You may proceed this way :
There are 2 distinct boxes (say A and B) and n distinct objects.
So each of n objects can go to either of the two boxes.
So total no. of possibilities = 2^n
Now the problem is, these 2^n cases contain two cases where:
# all objects are in box A
# all objects are in box B
These two cases make a box empty, which is prohibited. So we need to exclude these 2 cases.
So total no. of ways =( 2^n) - 2
But here n = 6
Hence answer = 2^6 - 2 = 64 - 2 ,= 62
Regards
Arun (askIITians forum expert)
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