The number of values of the pair (a,b) for which a(x+1)^2 + b{( – x^2) – 3x – 2} + x + 1 = 0 is an identity in x, is 1)0 2)1 3)2 4)Infinite

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Aditya Gupta · Answer

the eqn is: (x+1)[ax+a-b(x+2)+1]=0 or x(a-b)+a-2b+1=0 or a=b and a-2b+1=0 so a=b=1 option 2) is correct

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The number of values of the pair (a,b) for which a(x+1)^2 + b{( – x^2) – 3x – 2} + x + 1 = 0 is an identity in x, is 1)0 2)1 3)2 4)Infinite

The number of values of the pair (a,b) for which a(x+1)^2 + b{( – x^2) – 3x – 2} + x + 1 = 0 is an identity in x, is
1)0
2)1
3)2
4)Infinite

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The number of values of the pair (a,b) for which a(x+1)^2 + b{( – x^2) – 3x – 2} + x + 1 = 0 is an identity in x, is 1)0 2)1 3)2 4)Infinite

The number of values of the pair (a,b) for which a(x+1)^2 + b{( – x^2) – 3x – 2} + x + 1 = 0 is an identity in x, is1)02)13)24)Infinite

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The number of values of the pair (a,b) for which a(x+1)^2 + b{( – x^2) – 3x – 2} + x + 1 = 0 is an identity in x, is
1)0
2)1
3)2
4)Infinite