The number of real solutions of the equation (9/10)^x = – 3 +x – x^2 is..Please explain the solution.

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Aditya Gupta · Answer

we see that – 3 +x – x^2 = – [(x-1/2)^2+11/4] which is always less than zero. but LHS is (9/10)^x which is always greater than zero, hence no real solution exists

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The number of real solutions of the equation (9/10)^x = – 3 +x – x^2 is..Please explain the solution.

The number of real solutions of the equation (9/10)^x = – 3 +x – x^2 is..Please explain the solution.

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The number of real solutions of the equation (9/10)^x = – 3 +x – x^2 is..Please explain the solution.

The number of real solutions of the equation (9/10)^x = – 3 +x – x^2 is..Please explain the solution.

1 Answers

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