Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

the number of real roots of the equation:- 2x^2015 +3x^2014 +2x^2013 +3x^2012 +................+2x+3=0.

the number of real roots of the equation:-
2x^2015 +3x^2014 +2x^2013 +3x^2012 +................+2x+3=0.

Grade:Select Grade

1 Answers

Riddhish Bhalodia
askIITians Faculty 434 Points
5 years ago
This equation can be factorized as
2x(x^{2014}+x^{2012} + ... + 1) + 3(x^{2014}+x^{2012} + ... + 1) = 0
(2x+3)(x^{2014}+x^{2012} + ... + 1) = 0

so one root is -3/2
and the remaining factor is always positive and hence have no real root
so the equation has only one real root

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free