Grade 12th passAlgebra
the number of real &complex solutions ofx2-6|x|+8=0
the number of real &complex solutions of
x2-6|x|+8=0
1 Answer
Arun
if we assume x > 0
then we get x2 – 6x + 8 =0
x = 4, x = 2
now if assume x
we get
x2 + 6 x + 8 = 0
x = – 4, x = – 2
hence all solutions are x = 2, 4, – 2, – 4
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