For product of consecutive digits to be even one of thenumbers every alternate place should be even. So the cases wher the product of consecutive digits is not even when there exist two odd numbers together. So we count number of ways where atleast two odd digits are next to one another, and subtract it from total permutations.Total permutations = 8!Way to select 2 odd number = ^4C_2permutation with selected numbers together = 7!.2!Hencenumber of ways where atleast two odd digits are next to one another = ^4C_2.7!.2! – ways both odd numbers are consecutive(to prevent double counting)= ^4C_2.7!.2! - ^4C_2.2!2!6!Thus answer = 8! - ^4C_2.7!.2! + ^4C_2.2!2!6!
