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The no. of real solutions of x^4 – 5x^2 – 6x – 5= 0 os a. 0​b. 1​c. 3​d. 4

muktesh singh , 10 Years ago
Grade 11
anser 1 Answers
Sher Mohammad

Last Activity: 10 Years ago

(x^2-2)^2-x^2-6x-9=0
(x^2-2)^2-(x+3)^2=0
the function will be zero when
(x^2-2)^2=(x+3)^2
x^2-2=x+3 orx^2-2+x+3=0
x^2-x-5=0 0r x^2+x+1=0
the equation has two real solutions.
sher mohammad
faculty askiitians
b.tech, iit delhi

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