The mirror image of curve arg((z-3)/z-i))= pi/6, in the real axis isAns. arg((z+i)/(z-3))=pi/6Please tell me how to solve it
The mirror image of curve arg((z-3)/z-i))= pi/6, in the real axis is
Ans. arg((z+i)/(z-3))=pi/6
Please tell me how to solve it
Pushkar Kumar , 6 Years ago
Grade 12
