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```
the minimum value of (a+b+c)(1/a+1/b+1/c) is,(where a,b,c>0)
the minimum value of (a+b+c)(1/a+1/b+1/c) is,(where a,b,c>0)

```
3 years ago

Arun
25768 Points
```							we know that A.M. >= H.Mhencea+b+c /3 >=  3/ (1/a +1/b + 1/c)cross multiply (a+b+c)(1/a+1/b+1/c) > =  9 hence minimum value of expression will be 9
```
3 years ago
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