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Grade: 12th pass

                        

the minimum value of (a+b+c)(1/a+1/b+1/c) is,(where a,b,c>0)

3 years ago

Answers : (1)

Arun
24736 Points
							
we know that 
A.M. >= H.M
hence
a+b+c /3 >=  3/ (1/a +1/b + 1/c)
cross multiply 
(a+b+c)(1/a+1/b+1/c) > =  9
 
hence minimum value of expression will be 9
2 years ago
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