The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

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SHAIK AASIF AHAMED · Answer

Hello student, Lines perpendicular to same line are parallel to each other -p(p 2 +1)=(p 2 +1) p=-1 Hence there is only one value for p Thanks and Regards Shaik Aasif askIITians faculty

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The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

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The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

1 Answers

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Other Related Questions on Algebra

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