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The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

The line p(p2 + 1) x – y + q = 0 and (p2 + 1)2 x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for

Grade:12

1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
8 years ago
Hello student,
Lines perpendicular to same line are parallel to each other
-p(p2+1)=(p2+1)
p=-1
Hence there is only one value for p
Thanks and Regards
Shaik Aasif
askIITians faculty

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