the interior angles fo a polygon are inarithmatic

Question

the interior angles fo a polygon are inarithmatic progration.The smallest angle is 120 degree and the common difference is 5 degree.Find the number of sides?

Pratyush Ranjan Roul · Accepted Answer

the sequence seems to be 120, 125, 130 …..........So,Sn=n/2{ 240 + (n-1)5 }-----------------(i)but the angles can never be 180o as it does not form a vertex and hence no sideSo, it extend upto 175oSn also equals to n/2{a + an}Sn=n/2{120 + 175}--------- (ii)Equating i and ii,295 = 240 + 5n – 5=> 5n = 60=> n = 12

Algebra> the interior angles fo a polygon are inar...

the interior angles fo a polygon are inarithmatic progration.The smallest angle is 120 degree and the common difference is 5 degree.Find the number of sides?

Amit sharma , 8 Years ago

Pratyush Ranjan Roul

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Algebra> the interior angles fo a polygon are inar...

the interior angles fo a polygon are inarithmatic progration.The smallest angle is 120 degree and the common difference is 5 degree.Find the number of sides?

Amit sharma , 8 Years ago

Pratyush Ranjan Roul

LIVE ONLINE CLASSES

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