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Grade 10Algebra

The equation [ x – 1][x + 1] = a^2 – 2a – 3 can have real solutions for x if a belongs to

muthhu swami

12 Years agoGrade 10

1 Answer

Arun Kumar

Approved Tutor Answer12 Years ago

Hello Student,

$(x^2-1) = a^2-2a-3 \\=>a^2-2a-2 \geq 0 \\=>(a-1)^2-3 \geq 0 \\=>(a-1) \in (-\infty,\sqrt3] \bigcup [\sqrt3,\infty]$

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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