The equation [ x – 1][x + 1] = a^2 – 2a – 3 can ha

Question

The equation [ x – 1][x + 1] = a^2 – 2a – 3 can have real solutions for x if a belongs to

Arun Kumar · Accepted Answer

Hello Student,a^2-2a-2 \geq 0 \\=>(a-1)^2-3 \geq 0 \\=>(a-1) \in (-\infty,\sqrt3] \bigcup [\sqrt3,\infty] src=http://latex.codecogs.com/gif.latex?%28x%5E2-1%29%20%3D%20a%5E2-2a-3%20%5C%5C%3D%3Ea%5E2-2a-2%20%5Cgeq%200%20%5C%5C%3D%3E%28a-1%29%5E2-3%20%5Cgeq%200%20%5C%5C%3D%3E%28a-1%29%20%5Cin%20%28-%5Cinfty%2C%5Csqrt3%5D%20%5Cbigcup%20%5B%5Csqrt3%2C%5Cinfty%5D>Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty

Algebra> The equation [ x – 1][x + 1] = a^2 – 2a –...

The equation [ x – 1][x + 1] = a^2 – 2a – 3 can have real solutions for x if a belongs to

muthhu swami , 11 Years ago

Arun Kumar

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Algebra> The equation [ x – 1][x + 1] = a^2 – 2a –...

The equation [ x – 1][x + 1] = a^2 – 2a – 3 can have real solutions for x if a belongs to

muthhu swami , 11 Years ago

Arun Kumar

LIVE ONLINE CLASSES

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