# The equation of displacement of a particle is x=4t^2-6t+3.The acceleration at the moment when its velocity becomes 10m/s is?

Jitender Singh IIT Delhi
$x = 4t^{2}-6t + 3 (m)$
$v = 8t-6(\frac{m}{s})$
$a = 8 (\frac{m}{s^{2}})$