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The equation of displacement of a particle is x=4t^2-6t+3.The acceleration at the moment when its velocity becomes 10m/s is?

Srijan , 11 Years ago
Grade Upto college level
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
x = 4t^{2}-6t + 3 (m)
v = 8t-6(\frac{m}{s})
a = 8 (\frac{m}{s^{2}})
So acceleration is constant at all moments.
Thanks & Regards
Jitender Singh
IIT Delhi
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