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Grade Upto college levelAlgebra

The equation of displacement of a particle is x=4t^2-6t+3.The acceleration at the moment when its velocity becomes 10m/s is?

Srijan

12 Years agoGrade Upto college level

1 Answer

Jitender Singh

12 Years ago

Ans:

$x = 4t^{2}-6t + 3 (m)$

$v = 8t-6(\frac{m}{s})$

$a = 8 (\frac{m}{s^{2}})$

So acceleration is constant at all moments.

Thanks & Regards

Jitender Singh

IIT Delhi

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