Algebra> the equation of a circle,which passes thr...
1 AnswersLast Activity: 10 Years ago
Hello student,
Please find the answer to your question below
let the equation of required circle is x2+y2+2gx+2fy+c=0............(1)
As 1 passes through (2,0) and (0,2)
we get 4+4g+c=0 and 4+4f+c=0
so g=f=-(4+c)/2
Let r be the radius of circle (1) then
r=sqrt(g2+f2-c)
=sqrt(((4+c)/2)2+((4+c)/2)2-c)
=sqrt((c2+6c+16)/2)
so r2=(c2+6c+16)/2 is minimum when c=-3
so r=sqrt(7/2)
so g=f=-1/2
so equation of circle is x2+y2-x-y-3=0
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 1 Year ago
Last Activity: 1 Year ago
Last Activity: 2 Years ago
