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The digits of a three digit number forms a Gp. If we subtract 400 From it, then we get another 3 Digit Number whose digits Forms an Arithmetic series. What is The Sum Of These two Numbers?
Dear student Let the digits are x , y and z hence number is 100z + 10 y + x y^2 = xz Hence xz must be a square number xz = 9 hence y = 3 now some hit and trial,x = 1 , z= 9 hence number is 931 subtract 400,931 – 400 = 531 hence 931 + 531 = 1462
Let the digits are x , y and z hence number is 100z + 10 y + x y^2 = xz Hence xz must be a square number xz = 9 hence y = 3 now some hit and trial,x = 1 , z= 9 hence number is 931 subtract 400,931 – 400 = 531 hence 931 + 531 = 1462 Hope it helps RegardsArun (askIITians forum expert)
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