Grade 11Algebra
the coefficient of x^39 in expansion of (x^4-1/x^3)^15 is
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The general term is 15Cr(x^4)^15-r(-x^-3)^r = -15Cr(x)^60-7r so therefore 60-7r=39 from this r=3 so the coefficient of x^39 is - 15C3 = - 455
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