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`        the coefficient of x^39 in expansion of (x^4-1/x^3)^15 is`
2 years ago

## Answers : (1)

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```							The general term is    15Cr(x^4)^15-r(-x^-3)^r = -15Cr(x)^60-7r so therefore 60-7r=39 from this r=3 so the coefficient of x^39 is - 15C3 = - 455
```
2 years ago
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• 101 Video Lectures
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions