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        The chord of contact of the pair of tangents drawn from each point on the line 2x+3y=4 to the circle x^2+y^2 =1 pass through which point
2 years ago

ayush
29 Points
							Let any point on line be ((4-3t)/2,tThus equation of chord of contact given by: [T=0] will be [X(4-3t)/2 + Yt - 1=0] which will always pass through (1/2,3/4).

2 years ago
mycroft holmes
272 Points
							You are looking for the pole of the line 2x+3y=4 w.r.t to the circle x2+y2 = 1. If the point is (x1, y1), then the polar of the point would be xx1+yy1 = 1. Comparing with 2x+3y = 4, we immediately get $\frac{x_1}{2} = \frac{y_1}{3} =\frac{1}{4}$ so that x1 = ½, and y1 = ¾

2 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions