The centre of regular hexagonis at the point Z=i if one of its vertices is at 2+i , then the adjacent vertices of 2+i are at the points a)1 + 2i b)i+1 + 3 ½ c)2+i+(1 + 3 1/2 ) d)1+i(1 + 3 1/2 ) e)1-i(1 + 3 1/2 )

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venkateshwarrao · Answer

Given center Z° of the regular hexagon.Z1=2+I is the given vertex,let Z2 and Z6 be the adjacent vertices.Z2=Zo+(Z1-Zo)e^2πi/nZ2= i+(2+i-i)(1/2+i√3/2)=i+1+i√3=1+i(1+√3). similarlyZ6=1-i(1+√3). {Note:(Zn=Zo+(Z1--Zo)e^-(2πi/n}.

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The centre of regular hexagonis at the point Z=i if one of its vertices is at 2+i , then the adjacent vertices of 2+i are at the points a)1 + 2i b)i+1 + 3 ½ c)2+i+(1 + 3 1/2 ) d)1+i(1 + 3 1/2 ) e)1-i(1 + 3 1/2 )

The centre of regular hexagonis at the point Z=i if one of its vertices is at 2+i , then the adjacent vertices of 2+i are at the points a)1+2i b)i+1+3^½c)2+i+(1+3^1/2) d)1+i(1+3^1/2) e)1-i(1+3^1/2)

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The centre of regular hexagonis at the point Z=i if one of its vertices is at 2+i , then the adjacent vertices of 2+i are at the points a)1 + 2i b)i+1 + 3 ½ c)2+i+(1 + 3 1/2 ) d)1+i(1 + 3 1/2 ) e)1-i(1 + 3 1/2 )

The centre of regular hexagonis at the point Z=i if one of its vertices is at 2+i , then the adjacent vertices of 2+i are at the points a)1+2i b)i+1+3½ c)2+i+(1+31/2) d)1+i(1+31/2) e)1-i(1+31/2)

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The centre of regular hexagonis at the point Z=i if one of its vertices is at 2+i , then the adjacent vertices of 2+i are at the points a)1+2i b)i+1+3^½c)2+i+(1+3^1/2) d)1+i(1+3^1/2) e)1-i(1+3^1/2)