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`        Thanks chords of contact of the pair of tangents to the circle x^2+y^2=1 draw from any point on the line 2x+y=4 pass through (a,b) , then find a^2+b^2`
2 years ago

Arun
23478 Points
```							Hello AjayEquation of chord of contact:hx+ky=1(h, k) lie on the line, we have2h+k=4hx+(4-2h)y=4=>(1/2, 1/4)hence a = ½b = ¼now a^2 + b^2 = 1/4  + 1/16 = 5/16 RegardsArun (askIITians forum expert)
```
2 years ago
Ajay Pachankar
10 Points
```							I can`t understand these equation and how solve thisHow we get value of a and b from this plz help me and show how solve properly
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions