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Suppose the clock starts malfunctioning at 7 AM which decelerates the minute hand at the rate of 4Π radians/day. How much time would the clock loose by 7 AM next day? Plzz explain hw to solve it

Suppose the clock starts malfunctioning at 7 AM which decelerates the minute hand at the rate of 4Π radians/day. How much time would the clock loose by 7 AM next day?  Plzz explain hw to solve it

Grade:Select Grade

3 Answers

Aakash
110 Points
6 years ago
2(pi) =  1 rotation
2(pi) rotation means 60 minute
therefore
4(pi) rotation means 120 minute
In one day clock will lost 120 minute
 
Please Aprove if useful
Mohammad Kavish
36 Points
6 years ago
I am sorry to say Aakash but answer given is 1 hour
Aakash
110 Points
6 years ago
Angular speed of, 

minute hand : ωmh = 2π rad/hr = 48π rad/day 

Assume at t = 0, when the clock begins to malfunction

angle covered by the minute hand in one day = 48π(rad/day)

decelerates at a rate α = 4π (rad/day2)

So, angular displacement = ω0(1 day) – (1/2)α(1 day)2

           = 48π – (1/2)(4π)

           =  46π

Hence the minute hand complete 23 revolutions, so the clock losses 1 hour.

PLESE APROVE IF USEFUL

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