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`        Suppose A is any 3*3 non singular matrix and (A-3I)(A-5I)=0. If xA+bA'=4I , then x+b=  8 7 13 12`
one year ago

Deepak Kumar Shringi
4397 Points
```							i think it should be A -1at the place of A’ in the question please let me know
```
one year ago
Shrinithi sellam
14 Points
```							solve : (A - 3I)(A - 5I) = 0A.A - 5AI - 3IA + 15I² = 0A² - 5A - 3A + 15I = 0 [ as I² = I] A² - 8A + 15I = 0A² - 8A = -15I A^-1 (A²) - A^-1(8A) = -A^-1 .15I A - 8I = -15A^-1 A + 15A^-1 = 8I1/2 A + 15/2 A^-1 = 4I compare this to aA +bA^-1 = 4Iwe get, a =1/2 , b=15/2so, a+b=8hence, option (3) is correct.
```
10 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions