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Summation of r(r + 1)(r + 2)(r + 3) to n terms from 1?
Firstly,muktiply all the 4 terms as usual.and get the r terms in the power of 4, 3 ,2 and 1.And hence apply the summation formulae for that simply:For summation of r from n=1 to n is => n(n+1)/2for r^2 the summation is: => n(n+1)(2n+1)/6for r^3 it is: n^2(n+1)^2/4 and like this.
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