Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        Sum of infinite series  1/9+1/18+1/30+1/45+1/63...How do I solve the questionKindly give a detailed solution`
3 years ago

vivek
24 Points
```							9  18  30   45   t(n)=an^2+bn+c  9    12   15      9=a+b+c ; 18=4a+2b+c;           3      3          30=9a+3b+ca=3/2,b=9/2,c=3    for ques t(n)=2/3(1/(n+1)(n+2)sum(1 - infinity)= 2/3 (1/n+1 -  1/n+2 )=2/3 (1/2) =1/3
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions