Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy?

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SHAIK AASIF AHAMED · Answer

Hello student, &frac12; mv 2 =3/4(1/2)(vmax) 2 A 2 &omega; 2 cos 2 &omega;t =(3/4)A 2 &omega; 2 cos&omega;t= so&omega;t= t=1/6 sec Thanks and Regards Shaik Aasif askIITians faculty

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Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy?

Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy?

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Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy?

Starting from the origin, a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy?

1 Answers

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