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Square root of iota+square root of -iota.please answer

Jashan Singh , 7 Years ago
Grade 12
anser 1 Answers
Dinesh Nayak

Last Activity: 7 Years ago

the answer is
 
\sqrt[]{}\sqrt[]{i} + \sqrt[]{-i}  =  \sqrt[]{2}i
 
method 
first simplifiy the equation
\sqrt[]{i}+\sqrt[]{-i}= \sqrt{i}(1+i)
 
then let \sqrt{i}=a + ib
find the value of a and b and substitute in the equation and you will \sqrt{i} value
substitute it in the simplified main equation and you will get the answer

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