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Solving the quadratic equation.
Plz do help me with the problem.

Subhiksha , 10 Years ago
Grade 11
anser 2 Answers
jagdish singh singh
\hspace{-0.6cm}$Given $x^2+6ax+b=0$ has roots $\sqrt{3+\sqrt{8}} = 1+\sqrt{2}$\\\\So other root is $1-\sqrt{2}.$\\\\So $1+\sqrt{2}+1-\sqrt{2}=-6a$ and $(1+\sqrt{2})\cdot (1-\sqrt{2})=b$\\\\So we get $3a=-1$ and $b=-1$. So $15ab=5$
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Last Activity: 10 Years ago
Subhiksha
Its interesting that you wrote \sqrt{(3+\sqrt{8}} = 1 + \sqrt{2}
 
But is there any formula based on which you found it?? It could be useful..
Last Activity: 10 Years ago
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