# Solving the quadratic equation.Plz do help me with the problem.

$\hspace{-0.6cm}Given x^2+6ax+b=0 has roots \sqrt{3+\sqrt{8}} = 1+\sqrt{2}\\\\So other root is 1-\sqrt{2}.\\\\So 1+\sqrt{2}+1-\sqrt{2}=-6a and (1+\sqrt{2})\cdot (1-\sqrt{2})=b\\\\So we get 3a=-1 and b=-1. So 15ab=5$
Its interesting that you wrote $\sqrt{(3+\sqrt{8}} = 1 + \sqrt{2}$