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Solve ∣x²+4x+3∣=3 please explain fully .I am ot able to understand it.

Mudit , 8 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Dear Mudit,
∣x²+4x+3∣=3
mod always open with + and  – sign cases.
Therfore,
case 1 with + sign,
x²+4x+3= + 3
x²+4x = 0
x(x + 4) = 0
x = 0  and x = – 4
 
Case 2
x²+4x+3= – 3
x²+4x+6 = 0 
D
x²+4x+6 > 0
never zero therefore x belongs to null.
So the solutions are only x = 0 and x = – 4.

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