Solve ∣x²+4x+3∣=3 please explain fully .I am ot able to understand it.

Question

Vikas TU · Answer

Dear Mudit, ∣x²+4x+3∣=3 mod always open with + and – sign cases. Therfore, case 1 with + sign, x²+4x+3= + 3 x²+4x = 0 x(x + 4) = 0 x = 0 and x = – 4 Case 2 x²+4x+3= – 3 x²+4x+6 = 0 D x²+4x+6 > 0 never zero therefore x belongs to null. So the solutions are only x = 0 and x = – 4.

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Solve ∣x²+4x+3∣=3 please explain fully .I am ot able to understand it.

Solve ∣x²+4x+3∣=3 please explain fully .I am ot able to understand it.

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