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Solve ∣x²+4x+3∣=3 please explain fully .I am ot able to understand it. Solve ∣x²+4x+3∣=3 please explain fully .I am ot able to understand it.
Dear Mudit,∣x²+4x+3∣=3mod always open with + and – sign cases.Therfore,case 1 with + sign,x²+4x+3= + 3x²+4x = 0x(x + 4) = 0x = 0 and x = – 4 Case 2x²+4x+3= – 3x²+4x+6 = 0 D x²+4x+6 > 0never zero therefore x belongs to null.So the solutions are only x = 0 and x = – 4.
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