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Solve (x)2 = [x]2 + 2x Where [x] represents greatest integer less than or equal to x. (x) represents integer just greater than or equal to x
Solve (x)2 = [x]2 + 2xWhere [x] represents greatest integer less than or equal to x.(x) represents integer just greater than or equal to x

```
5 years ago

```							if x is not an integer, then [x] = (x)-1(x)=[x]+1(x) 2 = {[x]+1}2= [x]2 + 2[x] + 1 = [x]2 + 2x(acc to question) ie 2[x]+1= 2xie x-[x] = 0.5 so x belongs to {..., -1.5, -0.5, 0.5, 1.5, 2.5, ...} If x is an integer, then [x]=(x), and the eqn is satisfied for x= 0 so x belongs to  {..., -1.5, -0.5, 0, 0.5, 1.5, 2.5, ...}
```
5 years ago
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