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Solve the question given in the image .........?..…..............?...................

Solve the question given in the image .........?..…..............?...................

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Grade:12

1 Answers

Aditya Gupta
2081 Points
5 years ago
hello sarvesh. this ques is literally the easiest.
Sn+1= a1+a2+a3+....+an+a(n+1)
and Sn= a1+a2+a3+....+an
so that Sn+1 – Sn= a(n+1)
so in the given limit, the above term becomes a(n+1) as n tends to infinity. so the numerator tends to 2 (given).
however the denominator becomes n(n+1)/2 which tends to infinity as n tends to infinity.
so limit becomes 2/x where x tends to infinity.
hence L=0 (ZERO)

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